Optimal. Leaf size=160 \[ -\frac {1}{4} \sqrt {1+\frac {1}{\sqrt {2}}} \log \left (x^2-\sqrt {2+\sqrt {2}} x+1\right )+\frac {1}{4} \sqrt {1+\frac {1}{\sqrt {2}}} \log \left (x^2+\sqrt {2+\sqrt {2}} x+1\right )-\frac {\tan ^{-1}\left (\frac {\sqrt {2+\sqrt {2}}-2 x}{\sqrt {2-\sqrt {2}}}\right )}{2 \sqrt {2+\sqrt {2}}}+\frac {\tan ^{-1}\left (\frac {2 x+\sqrt {2+\sqrt {2}}}{\sqrt {2-\sqrt {2}}}\right )}{2 \sqrt {2+\sqrt {2}}} \]
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Rubi [A] time = 0.15, antiderivative size = 160, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 5, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.172, Rules used = {1169, 634, 618, 204, 628} \begin {gather*} -\frac {1}{4} \sqrt {1+\frac {1}{\sqrt {2}}} \log \left (x^2-\sqrt {2+\sqrt {2}} x+1\right )+\frac {1}{4} \sqrt {1+\frac {1}{\sqrt {2}}} \log \left (x^2+\sqrt {2+\sqrt {2}} x+1\right )-\frac {\tan ^{-1}\left (\frac {\sqrt {2+\sqrt {2}}-2 x}{\sqrt {2-\sqrt {2}}}\right )}{2 \sqrt {2+\sqrt {2}}}+\frac {\tan ^{-1}\left (\frac {2 x+\sqrt {2+\sqrt {2}}}{\sqrt {2-\sqrt {2}}}\right )}{2 \sqrt {2+\sqrt {2}}} \end {gather*}
Antiderivative was successfully verified.
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Rule 204
Rule 618
Rule 628
Rule 634
Rule 1169
Rubi steps
\begin {align*} \int \frac {\sqrt {2}-x^2}{1-\sqrt {2} x^2+x^4} \, dx &=\frac {\int \frac {\sqrt {2 \left (2+\sqrt {2}\right )}-\left (1+\sqrt {2}\right ) x}{1-\sqrt {2+\sqrt {2}} x+x^2} \, dx}{2 \sqrt {2+\sqrt {2}}}+\frac {\int \frac {\sqrt {2 \left (2+\sqrt {2}\right )}+\left (1+\sqrt {2}\right ) x}{1+\sqrt {2+\sqrt {2}} x+x^2} \, dx}{2 \sqrt {2+\sqrt {2}}}\\ &=\frac {1}{4} \sqrt {3-2 \sqrt {2}} \int \frac {1}{1-\sqrt {2+\sqrt {2}} x+x^2} \, dx+\frac {1}{4} \sqrt {3-2 \sqrt {2}} \int \frac {1}{1+\sqrt {2+\sqrt {2}} x+x^2} \, dx+\frac {\left (-1-\sqrt {2}\right ) \int \frac {-\sqrt {2+\sqrt {2}}+2 x}{1-\sqrt {2+\sqrt {2}} x+x^2} \, dx}{4 \sqrt {2+\sqrt {2}}}+\frac {\left (1+\sqrt {2}\right ) \int \frac {\sqrt {2+\sqrt {2}}+2 x}{1+\sqrt {2+\sqrt {2}} x+x^2} \, dx}{4 \sqrt {2+\sqrt {2}}}\\ &=-\frac {1}{4} \sqrt {1+\frac {1}{\sqrt {2}}} \log \left (1-\sqrt {2+\sqrt {2}} x+x^2\right )+\frac {1}{4} \sqrt {1+\frac {1}{\sqrt {2}}} \log \left (1+\sqrt {2+\sqrt {2}} x+x^2\right )-\frac {1}{2} \sqrt {3-2 \sqrt {2}} \operatorname {Subst}\left (\int \frac {1}{-2+\sqrt {2}-x^2} \, dx,x,-\sqrt {2+\sqrt {2}}+2 x\right )-\frac {1}{2} \sqrt {3-2 \sqrt {2}} \operatorname {Subst}\left (\int \frac {1}{-2+\sqrt {2}-x^2} \, dx,x,\sqrt {2+\sqrt {2}}+2 x\right )\\ &=-\frac {1}{2} \sqrt {\frac {1}{2} \left (2-\sqrt {2}\right )} \tan ^{-1}\left (\frac {\sqrt {2+\sqrt {2}}-2 x}{\sqrt {2-\sqrt {2}}}\right )+\frac {1}{2} \sqrt {\frac {1}{2} \left (2-\sqrt {2}\right )} \tan ^{-1}\left (\frac {\sqrt {2+\sqrt {2}}+2 x}{\sqrt {2-\sqrt {2}}}\right )-\frac {1}{4} \sqrt {1+\frac {1}{\sqrt {2}}} \log \left (1-\sqrt {2+\sqrt {2}} x+x^2\right )+\frac {1}{4} \sqrt {1+\frac {1}{\sqrt {2}}} \log \left (1+\sqrt {2+\sqrt {2}} x+x^2\right )\\ \end {align*}
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Mathematica [C] time = 0.04, size = 53, normalized size = 0.33 \begin {gather*} \frac {\sqrt {-1-i} \tan ^{-1}\left (\frac {\sqrt [4]{2} x}{\sqrt {-1-i}}\right )+\sqrt {-1+i} \tan ^{-1}\left (\frac {\sqrt [4]{2} x}{\sqrt {-1+i}}\right )}{2^{3/4}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt {2}-x^2}{1-\sqrt {2} x^2+x^4} \, dx \end {gather*}
Verification is not applicable to the result.
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fricas [C] time = 1.01, size = 97, normalized size = 0.61 \begin {gather*} \frac {1}{4} \, \sqrt {\left (i + 1\right ) \, \sqrt {2}} \log \left (x + \frac {1}{2} \, \sqrt {2} \sqrt {\left (i + 1\right ) \, \sqrt {2}}\right ) - \frac {1}{4} \, \sqrt {\left (i + 1\right ) \, \sqrt {2}} \log \left (x - \frac {1}{2} \, \sqrt {2} \sqrt {\left (i + 1\right ) \, \sqrt {2}}\right ) + \frac {1}{4} \, \sqrt {-\left (i - 1\right ) \, \sqrt {2}} \log \left (x + \frac {1}{2} \, \sqrt {2} \sqrt {-\left (i - 1\right ) \, \sqrt {2}}\right ) - \frac {1}{4} \, \sqrt {-\left (i - 1\right ) \, \sqrt {2}} \log \left (x - \frac {1}{2} \, \sqrt {2} \sqrt {-\left (i - 1\right ) \, \sqrt {2}}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.38, size = 122, normalized size = 0.76 \begin {gather*} \frac {1}{4} \, \sqrt {-2 \, \sqrt {2} + 4} \arctan \left (\frac {2 \, x + \sqrt {\sqrt {2} + 2}}{\sqrt {-\sqrt {2} + 2}}\right ) + \frac {1}{4} \, \sqrt {-2 \, \sqrt {2} + 4} \arctan \left (\frac {2 \, x - \sqrt {\sqrt {2} + 2}}{\sqrt {-\sqrt {2} + 2}}\right ) + \frac {1}{8} \, \sqrt {2 \, \sqrt {2} + 4} \log \left (x^{2} + x \sqrt {\sqrt {2} + 2} + 1\right ) - \frac {1}{8} \, \sqrt {2 \, \sqrt {2} + 4} \log \left (x^{2} - x \sqrt {\sqrt {2} + 2} + 1\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.09, size = 199, normalized size = 1.24 \begin {gather*} \frac {\sqrt {2}\, \arctan \left (\frac {2 x -\sqrt {2+\sqrt {2}}}{\sqrt {2-\sqrt {2}}}\right )}{2 \sqrt {2-\sqrt {2}}}-\frac {\arctan \left (\frac {2 x -\sqrt {2+\sqrt {2}}}{\sqrt {2-\sqrt {2}}}\right )}{2 \sqrt {2-\sqrt {2}}}+\frac {\sqrt {2}\, \arctan \left (\frac {2 x +\sqrt {2+\sqrt {2}}}{\sqrt {2-\sqrt {2}}}\right )}{2 \sqrt {2-\sqrt {2}}}-\frac {\arctan \left (\frac {2 x +\sqrt {2+\sqrt {2}}}{\sqrt {2-\sqrt {2}}}\right )}{2 \sqrt {2-\sqrt {2}}}-\frac {\sqrt {2}\, \sqrt {2+\sqrt {2}}\, \ln \left (x^{2}-\sqrt {2+\sqrt {2}}\, x +1\right )}{8}+\frac {\sqrt {2}\, \sqrt {2+\sqrt {2}}\, \ln \left (x^{2}+\sqrt {2+\sqrt {2}}\, x +1\right )}{8} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} -\int \frac {x^{2} - \sqrt {2}}{x^{4} - \sqrt {2} x^{2} + 1}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.96, size = 121, normalized size = 0.76 \begin {gather*} -\mathrm {atan}\left (x\,\sqrt {\frac {\sqrt {2}}{16}-\frac {\sqrt {8}\,1{}\mathrm {i}}{32}}\,2{}\mathrm {i}-\frac {\sqrt {2}\,\sqrt {8}\,x\,\sqrt {\frac {\sqrt {2}}{16}-\frac {\sqrt {8}\,1{}\mathrm {i}}{32}}}{2}\right )\,\sqrt {\frac {\sqrt {2}}{16}-\frac {\sqrt {8}\,1{}\mathrm {i}}{32}}\,2{}\mathrm {i}-\mathrm {atan}\left (x\,\sqrt {\frac {\sqrt {2}}{16}+\frac {\sqrt {8}\,1{}\mathrm {i}}{32}}\,2{}\mathrm {i}+\frac {\sqrt {2}\,\sqrt {8}\,x\,\sqrt {\frac {\sqrt {2}}{16}+\frac {\sqrt {8}\,1{}\mathrm {i}}{32}}}{2}\right )\,\sqrt {\frac {\sqrt {2}}{16}+\frac {\sqrt {8}\,1{}\mathrm {i}}{32}}\,2{}\mathrm {i} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: PolynomialError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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